Zundfolge,
Good find on the formula, but it's not applicable to the problem. It's true that a 150# shooter firing a .45 in space would be accelerated only to a speed of about 2-1/4 inches/second. If it was applicable, we would be seeing .50 BMG cartridges in handguns!
None of the poll choices are descriptive of what actually happens. Lift off never occurs -- that is a special effects fantasy.
A better physics description of the problem is a torque. The 150# target is assumed to be standing upright (feet parallel), and let's say his COM is at 4 feet above the ground. The muzzle energy of the 230 gr. slug is about 370 ft lbs, which is converted to a force applied to his COM of 92.5 pounds on the 4' lever tending to rotate the body about the axis of the feet. The earth supports all but a small fraction of the target's weight the entire time, and the slug never lifts him up-up-and-away at all.
Turns out that the problem can be empiracally simulated without shooting anybody and without resorting to half baked opinions.
A regulation baseball weighs about 5 ounces, and when at a velocity of about 59 mph has equivalent energy to a .45 slug. You need: a baseball, catcher's equipment, a 5' to 6' guy who will weigh 150# wearing the catcher's equipment, an accurate pitcher who can consistently hit the target with a 59 mph ball, a baseball chronograph, a blindfold, and a 2x4 board.
After the target is suited up, tape an "X" 4' above the ground. Have him stand relaxed and blindfolded with his heels against the 2x4. He won't see or hear the pitch coming so he won't flinch or brace himself. One accurate pitch, and what do you think will happen...?
Of course, you could just have somebody punch the target on the "X" with a force of 92.5#, but what fun would that be? You'd only need the chest protector, blindfold, 2x4, and maybe a boxing glove though.