Response part one
Bullet94,
I'll break this response into two or three parts. This first will just deal with the initial issue which was whether or not Al was right that a difference of only 1000 psi would result from a bullet touching the lands. I'll address the other points separately, as time allows, for anyone who is still interested. This is in order to keep the post character count within its limits.
First we need to clarify something with Al:
Al said:
“This is BRC for crying out loud.”
Not at this end. Al is posting in a bench rest shooting forum but I am not, except indirectly through Bullet94's copying of the posts between here and there. Ours is a general firearms forum. So when Al gets exercised because I mention Mid Tompkins, whose shooting he sees as irrelevant because it is not BR, that is so only at his end. Tompkins's loading technique is an example of properly developed loads that touch the lands and are useful for their purpose. I merely used him to be sure people reading the post understood that touching the lands intentionally is not always bad. I suspect Al would have preferred I had used Harold Vaughn's reference to this technique? On page 36-37 of Rifle Accuracy Facts, 2nd Edition, Vaughn says:
”Seating depth of a bullet in a case has an effect on just how close to the center a bullet will line up. Obviously, the bullet will be centered if it is in complete contact with the lands, however Reference 1 showed that peak chamber pressure decreases if a bullet has a free run before it contacts the lands. Since a minimum in peak pressure for a given load implies minimum bullet distortion, the author prefers a seating depth that will provide about 0.010 inches into the lands in the case of a bench rest gun with light bullets and about 0.020” off the lands in the case of a sporter using heavier bullets.”
I should add, since Vaughn puts faith in it, that “Reference 1”, above, is a book called Absolute Chamber Pressure in Center Fire Rifles, by Brownell, York. Sinderman, Jacobs, and Robbins, University of Michigan, Ann Arbor, Michigan. 1965. That is awhile ago, but it gives you the source of the numbers Vaughn believes. If you can find a copy, you can look them up.
Al said:
I'll start with Nicks interpretation of my answers........
1.) Harold Vaughn measured a bullet engraving pressure at 1000 to 1500 psi, and that is not enough force to account for the 22% peak pressure increase on the graphs.
2.) No velocity increase appeared, so no pressure increase could have occurred.
3.) A number of people have had difficulty using the Pressure Trace instrument, so a readout from it should not be trusted.
In fact NONE of these assertions are mine....
Well, let me quote from Al's first reply to appear on this forum. This is what I took assertion 1.) from:
Al said:
Without going into endless detail, suffice it to say that theoretical data agree with directly MEASURED data in this instance. The real difference between thirty thou out and touching the lands is around 1000psi.
This is what I took assertions 2.) and 3.) from:
Al said:
I've had calls and letters from quite a few folks who own RSI systems. They're constantly confronted with "pressure trace" readings which show HUGE increases in pressure while reading only modest increases in velocity. A difference of 25% from one shot to the next isn't "modest"!! A 25% increase in pressure is hellacious..........and should result in a velocity increase to match the pressure spike.
This is where Al reinforced assertion 3.):
Al said:
.......far from "dangerous" and FAR from "25%". It seems that the data presented by the RSI pressure traces increases this effect by a factor of 10!
If I somehow misunderstood those statements, I'll leave it to Al to explain them and how they do not comprise his assertions?
Al said:
Furthermore confusing is the fact that Nick goes on to restate WITH DETAIL and corroboration from Vaughn EXACTLY what I was saying........??? ......I'm not sure what to make of it.......
No. It was
not “EXACTLY” what Al was saying. That was the whole point of my posting it. Al misused Vaughn's units. I went through the calculations using the units correctly to show the correct result is almost 17 times more pressure than Al claimed Vaughn's measurement represents. Al said the difference in pressure created by a bullet touching the lands was “1000 psi”. 1000 psi produces only 60 lbs of force on a .277” diameter bullet; enough to seat a bullet in a case, but not enough to engrave squat.
Al said:
Nick takes this to mean that the difference between touching and not touching is 10,000psi.
WRONG! This isn't what Harold's saying A'tall.......
Yes, it is exactly what Vaughn is saying if you know what the units mean. That is what brings us to the basis of this whole disagreement. In my first post I tried to leave Al some wiggle room when I suggested he misremembered the data and didn't point out his unit inconsistencies. Al does not seem to have been able to follow that, so I will resort to being blunt. The complete and accurate quote from Al's first post, with bold type added by me to emphasize the inconsistency was:
Al said:
Without going into endless detail, suffice it to say that theoretical data agree with directly MEASURED data in this instance. The real difference between thirty thou out and touching the lands is around 1000psi. The maximum difference that one could realize would not exceed 1500lb.
From that statement, it is apparent that Al believes psi and lbs mean the same thing and are interchangeable. They do not, and are not. Pounds are units of force, and psi are units of pressure. Pressure is the distribution of force, that is, how much force is applied a whole unit of area, not how much force is applied to the small portion of that area a bullet or bore represents. In this case, pressure is the number of pounds force seen by each full square inch of chamber, including the small portion the bullet base occupies. Most bullets are nowhere near a whole square inch in cross-sectional area, so the number of those pounds of force it intercepts is a fraction of what a whole square inch sees, and is therefore a fraction of the magnitude (size) of the pressure number. 1,000 psi, Al's first number, would apply only about 60 lbs of force to a .270 bullet, while 1500 lbs force, Al's second number, would require about 25,000 psi to apply it to that same bullet. Force and pressure numbers would only be the same if the bullet were a full square inch in cross-sectional area (about 113 caliber).
Mechanics who work with hydraulics and pneumatics often drop “per square inch” to shorten “pounds per square inch” just to “pounds” in their vernacular. But such slang does not allow accurate calculations to be made where more than one unit is involved. That is why neither physicists nor Harold Vaughn truncate the terminology in that way. Al clearly does not understand the basic physics units and their the pressure and force relationship. He quite openly states he doesn't understand why the gravitational constant plays a roll in the relationship of units of weight and mass and force. Understanding units and familiarity with how units work in calculations are tools necessary to calculate pressure accurately. Without them you can only get correct results by accident.
I don't intend to write a basic physics text here. If anyone else reading this missed the chance to take basic physics in high school, and wants to learn what's needed for calculations of the type described here, I would recommend getting a copy of The Cartoon Guide to Physics (no, that's not a joke, it is the actual title, and the book does have lots of non-threatening cartoon illustrations) by Larry Gonick. It is a relatively easily understood introductory physics book.
Al said:
What Harold Vaughn is saying is that it takes 20,000lb to overcome the "breakaway force" and engrave the bullet but only 10,000lb THEREAFTER to keep it sliding. This all has nothing to do with whether or not the bullet is in or out of the lands. . .
. . . Soooooooo, I at least THINK I've located the spot where Nick's interpretation of Vaughn's data led him to an erroneous assumption which of course leads inexorably to erroneous conclusion.
OR NOT!!!
Not. First, again, as in Al's other posts, the units are wrong. 20,000lb, would require 331,800 psi acting on Vaughn's bullet. 10,000 lbs would need 165,900 psi. But assuming Al meant to say 20,000 psi and 10,000 psi, then what's his point? Does he think a drop in friction will drop pressure? Once the compressed gas is present to make 20,000 psi, it would require Captain Kirk beaming half the gas out of the chamber at the moment the bullet started moving to drop that pressure in half. I am not a member of Star Fleet, but I am reasonably confident that isn't being done. Once the bullet starts to move, it is not merely kept sliding, but is also rapidly accelerated. Under rapid acceleration, the main resistance against which burning powder builds pressure is the reaction force presented by the inertia of the bullet mass, not that of the friction. When gas pressure builds to 20,000 psi to start a bullet moving, the burning powder just keeps building pressure from there until the peak is reached.
The role of start pressure in this discussion has been that it is different when the bullet touches the lands at the throat than when it does not. In the former case the value is higher. Subsequent sliding friction isn't relevant to that. Higher start pressure causes the chamber pressure peak to be reached earlier in the bullet's travel
time down the bore. This is because the added time needed to build to that higher start pressure has allowed more powder to get burning before the bullet began to move. That's the additional hesitation I referred to in my earlier post that is above and beyond the hesitation in the neck of a bullet seated off the lands. The higher start pressure will accelerate the sliding bullet faster in the early part of its travel, so the bullet distance down the bore at peak pressure will not shorten by much. It will, however, shorten a little and contribute an additional couple of percent or so to the pressure peak above and beyond the difference in start pressures. It is important to keep in mind the difference in start pressure is not the end concern here, but rather it is the difference in peak pressure that results from the difference in start pressure.
To summarize, in this post I have shown Al's pressure difference numbers were wrong because he doesn't understand how the units work, resulting in his assumption that force numbers were the same magnitude as pressure numbers. In reality these are almost 17 times bigger in the case of the .277" bullets. They are almost 22 times bigger for 6 mm. Once that is understood, the 22% gain in pressure shown in the plots I included in my first post fall well within that range and are perfectly reasonable. In the prior post I showed the pressure plots were accurate. Either clipping the bottom or introducing a non-linear exaggeration of peak values would require the muzzle pressure values shown to be unrealistically low. Instead the pressure shown at the end of the plots are corroborated by computer modeling.
Nick