brickeyee,
That is why I specified subsonic only in my solution. I think that even if the bullet leaves the muzzle supersonically, as long as it 'quickly' slows to subsonic speeds (going straight up against gravity and air), the v^2 solution should give a reasonable approximation.
I think the general solution for the case where the trajectory is not vertical must be solved numerically because we would have two coupled differential equations. Vertical travel makes things a lot simpler!
That is why I specified subsonic only in my solution. I think that even if the bullet leaves the muzzle supersonically, as long as it 'quickly' slows to subsonic speeds (going straight up against gravity and air), the v^2 solution should give a reasonable approximation.
I think the general solution for the case where the trajectory is not vertical must be solved numerically because we would have two coupled differential equations. Vertical travel makes things a lot simpler!