Josh17 said:
...What I don’t understand is how??
I do have small hands and the G43 fits like a glove....
That's how. It's as simple as that.
Recoil energy and felt (perceived) recoil are two different things.
Felt recoil is a subjective matter. Various factors can affect how recoil is perceived. Gun fit can be a major influence, and things like the thickness and angle of the grip are some of the attributes of gun fit which can influence how one perceives recoil. Someone with small hands will get a better, firmer grip on a gun with a smaller around grip and will therefore be better able to manage the recoil compared to a gun with a larger, bulkier grip.
I was, a while ago, able to do a very direct comparison. I have a couple of Glock 19s. I can generally manage them quite well in stock form. But I decided to send them off to ROBAR for their grip reduction. I was able to feel the difference and find my modified Glock 19s easier to control. They feel like they have less recoil.
Recoil energy on the other hand is a precise, physical quantity that is a function of the weight (mass) of the bullet, the weight (mass) of the powder charge, the muzzle velocity of the bullet, the muzzle velocity of the powder gases, and the weight (mass) of the gun. If you have those quantities for a given load in a given gun, you can calculate the amount of recoil energy produced when that load is fired in that gun. And a heavy bullet will produce more recoil energy than a lighter bullet fired from the same gun at a comparable velocity. Note that --
- Recoil energy is directly proportional to the mass of the ejecta, i. e., recoil energy increases as the mass of the ejecta increase. The mass of the ejecta is made up of --
- The mass of the bullet; and
- The mass of the gases produced by the burning powder (which is directly proportional to the mass of the powder charge).
- Recoil energy is directly proportional to the velocity of the ejecta, i. e., recoil energy increases as the mass of the ejecta increase. The velocity of the ejecta includes --
- The velocity of the bullet; and
- The velocity of the burning powder gases.
- Recoil energy is inversely proportional to the mass of the gun, i. e., as the mass of the gun increases, recoil energy decreases.
If you're interested, you can calculate the recoil energy of a given load using the following formula
1:
WG = Weight of gun in pounds
WB = Weight of bullet in grains
WP = Weight of powder charge in grains
VB = Muzzle velocity of bullet in f/s
I = Interim number (Recoil Impulse in lb/sec)
VG = Recoil velocity of gun (f/s)
EG = Recoil energy of gun (ft lb)
I = [(WB * VB) + (WP * 4000)] / 225218
VG = 32.2 * (I / WG)
EG = (WG * VG * VG) / 64.4
My modified Glock 19s should actually produce slightly more recoil energy. The ROBAR grip reduction involves taking some material away from the gun reducing its overall mass (albeit not by much). Nonetheless they feel like they recoil less.
________________________
1.
This formula is quite similar to a formula for free recoil set out at http://en.wikipedia.org/wiki/Free_recoil, although I think that the formula from Wikipedia may be a little more precise based on what I've read in Hatcher's Notebook. The formula I've reproduced above, is from the Q&As at http://www.frfrogspad.com/miscella.htm (specifically the question about why some guns of the same caliber kick harder than others). John Schaefer (FrFrog) notes that, "..."4000" is the nominal velocity of the powder gases at the muzzle for commercial smokeless powder and the observed range is between 3700 and 4300 f/s. It is sometimes stated as 4700 in some sources but this is based on observations of artillery, not small arms...." The Wikipedia formula would use the actual powder gas velocity, which may not be readily available.